Solve Triangle: a=5, b=12, c=13

Complete solution for the triangle with given measurements. Find all missing sides, angles, area, and perimeter.

Side a: Side b: Side c:
Area: 30 sq units
Perimeter: 30 units
Step-by-Step Solution
Step 1 Given Information

Sides: a = 5, b = 12, c = 13

Angles: A = ?°, B = ?°, C = ?°

Step 2 Method: SSS (Side-Side-Side)

All three sides are known

Use Law of Cosines to find angles

Step 3 Find Angles (Law of Cosines)

cos(A) = (b² + c² - a²) / (2bc) = 0.9231

A = 22.62°

cos(B) = (a² + c² - b²) / (2ac) = 0.3846

B = 67.38°

C = 180° - A - B = 90°
Step 4 Calculate Area (Heron's Formula)

s = (a + b + c) / 2 = 15

Area = √[s(s-a)(s-b)(s-c)]

Area = √[15 × 10 × 3 × 2]

Area = 30

Step 5 Perimeter

P = a + b + c = 30

Step 6 Triangle Classification

Scalene (no sides equal)

Right triangle (one 90° angle)

Step 7 Final Answer
A = 22.62°, B = 67.38°, C = 90°, Area = 30

Triangle Solution Methods

SSS (3 sides): Use Law of Cosines for angles, Heron's for area

SAS (2 sides, included angle): Use Law of Cosines

ASA/AAS (2 angles, 1 side): Use Law of Sines