Solve x² + 4x + 5 = 0
Solve the quadratic equation x² + 4x + 5 = 0 using the quadratic formula.
Solution:
Discriminant: Δ = -4 (2 complex roots)
Step-by-Step Solution
Step 1
Identify the Standard Form
A quadratic equation has the form: ax² + bx + c = 0
From the given equation:
• a = 1 (coefficient of x²)
• b = 4 (coefficient of x)
• c = 5 (constant term)
Standard form: x² + 4x + 5 = 0
x² + 4x + 5 = 0
Step 2
Calculate the Discriminant
The discriminant determines the nature of the roots.
D = b² - 4ac
D = (4)² - 4(1)(5)
D = 16 - 20
D = -4
Since D = -4 < 0, the equation has two COMPLEX roots.
D = -4
Step 3
Apply the Quadratic Formula for Complex Roots
Since D < 0, we have complex roots.
The quadratic formula gives:
x = (-b ± √D) / 2a
With D = -4 < 0:
√D = √(4) × i = 2i
\sqrt{D} = 2i
Step 4
Calculate Complex Solutions
Real part: -b/(2a) = -4/2 = -2
Imaginary part: √|D|/(2a) = 2/2 = 1
The solutions are:
x₁ = -2 + 1i
x₂ = -2 - 1i
These are complex conjugates.
x = -2 \pm 1i
Step 5
Final Answer
x = -2 ± 1i