Solve x² - 4 = 0

Solve the quadratic equation x² - 4 = 0 using the quadratic formula.

x² + x + = 0
Solution:
Discriminant: Δ = 16 (2 real roots)
Step-by-Step Solution
Step 1 Identify the Standard Form

A quadratic equation has the form: ax² + bx + c = 0


From the given equation:

• a = 1 (coefficient of x²)

• b = 0 (coefficient of x)

• c = -4 (constant term)


Standard form: x² - 4 = 0

x² - 4 = 0
Step 2 Calculate the Discriminant

The discriminant determines the nature of the roots.


D = b² - 4ac

D = (0)² - 4(1)(-4)

D = 0 - -16
D = 16

Since D = 16 > 0 and √D = 4 (perfect square),

the equation has two distinct RATIONAL roots.

D = 16
Step 3 Solve by Square Root Method

Since b = 0, this is a pure quadratic equation:


1x² + -4 = 0


We can solve directly by isolating x².

1x^2 + -4 = 0
Step 4 Isolate x² and Take Square Root

1x² = 4

x² = 4


Taking the square root of both sides:

x = ±√4


x₁ = +2

x₂ = -2

x = \pm2
Step 5 Verify the Solutions

Substitute each solution back into the original equation:


For x = 2:

1(2)² + 0(2) + -4

= 0 ✓


For x = -2:

1(-2)² + 0(-2) + -4

= 0 ✓

\text{Both solutions verified!}
Step 6 Final Answer

x = -2 or x = 2